Find the radius of a circle, if the area of the big square is 30 square units more than the area of the small square.

The radius of the given circle is;
R = ½[x + √(x² + 30)]
Let the side of the small square be x.
We are told that the radius of the big square is 30 square units more than the area of the small square.
Thus;
Area of big square = x² + 30
Area of small square = x²
Thus, side of big square = √(x² + 30)
Then diameter of circle = side of small square + side of big square
Thus;
Diameter of circle = x + √(x² + 30)
Thus, the radius of the circle is;
R = ½[x + √(x² + 30)]
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