Question

write this equation in standard form
9x^2-4y^2-24y-72=0

Answer 1

$9x^2-4y^2-24y-72=0\\ \\ 9x^2-4y^2-24y=72\\ \\ 9x^2-(4y^2+24y+36)=72-36\\ \\ 9x^2-4(y+3)^2=36\\ \\ \frac{9x^2}{36}-\frac{4(y+3)^2}{36}=\frac{36}{36}\\ \\ \boxed{\frac{x^2}{4}-\frac{(y+3)^2}{9}=1}$