[tex]\qquad \qquad\huge \underline{\boxed{\sf Answer}}[/tex]
Let's solve ~
[tex]\qquad \sf \dashrightarrow \: 22.4 \: L = 1 \: mole[/tex]
[tex]\qquad \sf \dashrightarrow \:1 \: L = \dfrac{1}{22.4} \: mole[/tex]
[tex]\qquad \sf \dashrightarrow \: 134.4 \: L = \dfrac{1}{22.4} \times 134.4 \: moles[/tex]
[tex]\qquad \sf \dashrightarrow \: 134.4 \: L = 6 \: moles[/tex]
Therefore, correct choice is A.)