Question

The student collects the h2(g) produced by the reaction and measures its volume over water at 298 k after carefully equalizing the water levels inside and outside the gas-collection tube, as shown in the diagram below. The volume is measured to be 45. 6ml. The atmospheric pressure in the lab is measured as 765 torr , and the equilibrium vapor pressure of water at 298 k is 24 torr.

Answer 1

The total pressure of hydrogen gas inside the tube is; P_h2 = 741 torrs

Dalton's Law of partial pressure

We are given;

• The atmospheric pressure measured in the lab; P_total = 765 torr
• Vapor pressure of water; P_h2O = 24 torr

By applying Dalton's Law of Partial Pressure to this problem, we have the formula:

P_total = P_h2 + P_h2O

Where;

P_h2 is the pressure of hydrogen inside the tube.

Thus, making P_h2 the subject we have;

P_h2 = P_total - P_h2O

P_h2 = 765 - 24

P_h2 = 741 torrs

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