Question

A pear and a papaya are placed 12 meters apart from
each other. The pear is 0.005 kg and the papaya is 0.008
kg. Calculate the force of gravitation between them.

Answer 1

The force of gravitation between the pear and a papaya is equal to $1.85 \times 10^{-17}\;Newton$

Given the following data:

• Mass of pear = 0.005 kg

• Mass of person = 0.008 kg

• Radius = 12 meters

Scientific data:

• Gravitational constant = $6.67\times 10^{-11}$

To calculate the force of gravitation between the pear and a papaya, we would apply Newton's Law of Universal Gravitation:

Mathematically, Newton's Law of Universal Gravitation is given by this formula:

$F = G\frac{M_1M_2}{r^2}$

Where:

• F is the gravitational force.

• G is the gravitational constant.

• M is the mass of objects.

• r is the radius or distance between centers of the masses.

Substituting the given parameters into the formula, we have;

$F = 6.67\times 10^{-11} \times \frac{(0.005 \times 0.008)}{12^2}\\\\F = 6.67\times 10^{-11}\times \frac{0.00004 }{144}\\\\F = \frac{2.668 \times 10^{-15} }{144}\\\\F = 1.85 \times 10^{-17}\;Newton$

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