john rowed his boat against the current for 3 hours. The return trip with the current took 2 hours. What is Johns speed in still water if the speed of current is 2mph

Respuesta :

Answer:

Step-by-step explanation:

Formula

d = r * t

Givens

Let his speed in still water = x

The trick to this question is that the distance is the same both ways.

time with the current = 2 hours.

Time against the current = 3 hours

rate of the current (it's always the same) 2 mph

d = (x + 2)*2 going with the current

d = (x - 3)*3 going against the current.

(x + 2)*2 = (x - 3)*3                Remove the brackets.

2x + 4 = 3x- 9                       Add 9 to both sides.

2x + 4 + 9 = 3x                     Combine

2x + 13 = 3x                           Subtract 2x from both sides.

13 = 3x - 2x

13 = x

So his boat would go 13 mph is still water.

So sin

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