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The standard deviation is 1.98. Option A is correct.

The standard deviation formula is given as

  • [tex]\sigma = \sqrt{\frac{SS}{n} }[/tex]

where:

  • SS is the sum of squares = 200
  • n is the sample size = 51

Substitute the given parameters into the formula to have:

[tex]\sigma = \sqrt{\frac{200}{51} }\\\sigma = \sqrt{3.922}\\\sigma = 1.980[/tex]

Hence the standard deviation is 1.98

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