Question

4. Initially, 1 mol of oxygen (assumed to be an ideal gas) has temperature 310 K and volume 12 L. We will allow it to expand to volume 19 L. (a) What would be the final temperature if the gas expands adiabatically

Answer 1

Answer:

490.83 oK

Explanation:

First of all, we better agree on the meaning of the word adiabatically. It means without the loss or gain of heat. So nothing is given up to or taken from the environment.

This also assumes that no change has occurred in the pressure.

T1 = 310 oK

T2 = ?

V1 = 12 L

V2 = 19 L

T1/V1 = T2/V2

310 / 12 = x/19            Multiply both sides by 19

310*19 / 12 = T2         Multiply 310 * 19 on the left.

5890 / 12   = T2         Divide by 12

490.83 = T2