Answer:
No real solutions
Step-by-step explanation:
First, set it to equal to zero.
5x2−3x=−8
5x2−3x+8=0
If factoring the quadratic equation doesn't solve the
problem, use the quadratic formula as a last resort to find
xx=−b±√b2−4ac2a when a=5,b=−3,c=8
x=−(−3)±√(−3)2−4(5)(8)2(5)=3±√9−16010
Now if you look at the discriminant which is b2−4ac, is negative. The discriminant tells you how many real solutions are in the equation.
remember this:
when b2−4ac<0 is negative , there are no real solutions
when b2−4ac=0 is zero, there is one real solution
when b2−4ac>0 is positive, there are two real solutions
so the answer is that there are no real solutions
