Question

54.0 g Al creates up to 102 g Al2O3 and 64.0 g O2 creates up to 136 g Al2O3.

What is the theoretical yield (amount of Al2O3 formed) for this reaction?

[?] g Al₂O3

Answer 1

The theoretical yield of the product is 204 g of the product .

What is the theoretical yield?

The theoretical yield is the yield of the reaction as obtained from the stoichiometry of the reaction.  

The reaction equation is given as 4Al + 3O2 → 2Al2O3

Number of moles of Al = 54.0 g/27 g/mol = 2 moles

Number of moles of oxygen = 64.0 g/32 g/mol = 2 moles of O2

Hence,

If 4 moles of Al yields 2 moles of Al2O3 then 204 g of the product is obtained.

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