Use the sine tool to graph the function. The first point must be on the midline and the second point must be a maximum or minimum value on the graph closest to the first point.
The midline here is y = 0, which is right on top of the horizontal x axis. One point on the curve that's on the midline is the origin (0,0). This is marked as point A in the diagram below.
Point B is one of the infinitely many minimum points, aka lowest point. We determine this by noticing that sin(x) maxes out when x = pi/2 = 1.57 approximately. You should find that this x value leads to y = -2. So the location of point B is approximately (1.57, -2).
I used GeoGebra to make the graph. Desmos is another option you can use. Both are free.
