1. A retirement account is opened with an initial deposit of $8,500 and earns 8.12% interest compounded monthly. What will the account be worth in 20 years? What if the deposit were compounded monthly with simple interest? Could you see the situation in a graph? From what point one is better than the other?

Respuesta :

Answer:

Part A) [tex]\$42,888.48[/tex]  

Part B) [tex]A=\$22,304[/tex]

Part C) The graph in the attached figure

Step-by-step explanation:

Part A) What will the account be worth in 20 years?

we know that    

The compound interest formula is equal to  

[tex]A=P(1+\frac{r}{n})^{nt}[/tex]  

where  

A is the Final Investment Value  

P is the Principal amount of money to be invested  

r is the rate of interest  in decimal

t is Number of Time Periods  

n is the number of times interest is compounded per year

in this problem we have  

[tex]t=20\ years\\ P=\$8,500\\ r=0.0812\\n=12[/tex]  

substitute in the formula above  

[tex]A=8,500(1+\frac{0.0812}{12})^{12*20}[/tex]  

[tex]A=8,500(1.0068)^{240}[/tex]  

[tex]A=\$42,888.48[/tex]  

Part B) What if the deposit were compounded monthly with simple interest?  

we know that

The simple interest formula is equal to

[tex]A=P(1+rt)[/tex]

where

A is the Final Investment Value

P is the Principal amount of money to be invested

r is the rate of interest  

t is Number of Time Periods

in this problem we have

[tex]t=20\ years\\ P=\$8,500\\r=0.0812[/tex]

substitute in the formula above

[tex]A=8,500(1+0.0812*20)[/tex]

[tex]A=\$22,304[/tex]

Part C) Could you see the situation in a graph? From what point one is better than the other?

Convert the equations in function notation

[tex]A(t)=8,500(1.0068)^{12t}[/tex] ------> equation A

[tex]A(t)=8,500(1+0.0812t)[/tex]  -----> equation B

using a graphing tool  

see the attached figure  

Observing the graph, from the second year approximately the monthly compound interest is better than the simple interest.

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