Question

A package contains 4 red, 2 green, 8 purple, and 6 blue jelly beans. What is the probability of choosing a purple jelly bean, eating it, and then choosing a blue jelly bean? StartFraction 1 over 400 EndFraction StartFraction 1 over 380 EndFraction StartFraction 3 over 25 EndFraction StartFraction 12 over 95 EndFraction.

Answer 1

Probability of choosing a purple jelly bean, eating it, and then choosing a blue jelly bean is; 12/95

We are given the contents of the package as;

Red jelly beans = 4

Green jelly beans = 2

Purple jelly beans = 8

Blue jelly beans = 6

Total number of jellybeans = 4 + 2 + 8 + 5 = 20

Probability of selecting a purple jelly bean and eating it = 8/20

After picking one, we are left with 19 jellybeans. Thus;

Probability of picking a blue jelly bean and eating it = 6/19

Thus;

Probability of choosing a purple jelly bean, eating it, and then choosing a blue jelly bean = 8/20 × 6/19 = 48/380 = 12/95

Read more about probability selection at; https://brainly.com/question/1274894

Answer 2

Answer: choosing a purple jelly bean, eating it, and then choosing a blue jelly bean = 8/20 × 6/19 = 48/380 = 12/95

Step-by-step explanation:

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