Question

From his eye, which stands 1.62 meters above the ground, Amadou measures the
angle of elevation to the top of a prominent skyscraper to be 44°. If he is standing at a
horizontal distance of 164 meters from the base of the skyscraper, what is the height
of the skyscraper? Round your answer to the nearest tenth of a meter if necessary.

Answer 1

The height  of the skyscraper rounded to the nearest tenth of a meter is

160.0 meters.

The situation will form a right angle triangle.

The angle of elevation is 44 degrees. The horizontal distance of 164

meters from the base of the skyscraper is the adjacent side of the triangle.

Part of the height of the skyscraper is the opposite side of the triangle formed .

Using trigonometric ratio,

tan 44° = opposite / adjacent

tan 44° = h / 164

cross multiply

h = 164 × tan 44°

h = 158.372959068

Recall the angle of elevation was form from his eyes above the ground of

1.62 meters.

Therefore, the height of the skyscraper can be calculated below:

height of the skyscraper = 158.372959068 + 1.62 = 159.992959068

height of the skyscraper ≈ 160.0 meters

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