Answer:
The coordinates of the division point are (0.8 , 1.4)
Step-by-step explanation:
* Lets explain how to find the point of division
- If point (x , y) divide the line whose endpoints are [tex](x_{1},y_{1})[/tex]
and [tex](x_{2},y_{2})[/tex] at the ratio [tex]m_{1}:m_{2}[/tex] from point
[tex](x_{1},y_{1})[/tex], then [tex]x=\frac{x_{1}m_{2}+x_{2}m_{1}}{m_{1}+m_{2}}[/tex] and [tex]y=\frac{y_{1}m_{2}+y_{2}m_{1}}{m_{1}+m_{2}}[/tex]
* Lets solve the problem
∵ The endpoint of CD are (-4 , 3) and (8 , -1)
∵ Point (x , y) divides CD directed from C to D at ratio 2 : 3
- By using the rule above
∵ Point (-4 , 3) is [tex](x_{1},y_{1})[/tex]
∵ Point (8 , -1) is [tex](x_{2},y_{2})[/tex]
∵ [tex]m_{1}=2[/tex] and [tex]m_{2}=3[/tex]
∴ [tex]x=\frac{(-4)(3)+(8)(2)}{2+3}=\frac{-12+16}{5}=\frac{4}{5}[/tex]
∴ [tex]y=\frac{(3)(3)+(-1)(2)}{2+3}=\frac{9+-2}{5}=\frac{7}{5}[/tex]
∵ The x-coordinate of the point is 4/5 = 0.8
∵ The y-coordinate of the point is 7/5 = 1.4
∴ The coordinates of the division point are (0.8 , 1.4)