Question

a tube of constant circular cross-section, sealed at on end, contains an ideal gas trapped by a cylinder of mercury of length 0.035m. The whole arrangement is in the Earth's atmosphere. The density of mercury is 1.36*10^4, more details provided in the images.

Answer 1

Answer:

P V = N R T      ideal gas equation

V = .19 * A      volume of enclosed gas

.19 P = N R T / A      using volume of enclosed gas

P = Po + Phg       pressure on gas = atmospheric (Po) + Phg pressure due to column of mercury

.19 (Po + Phg) = N R T / A which is what was asked

Note Phg = density of Hg * height of Hg * acceleration due to gravity