Answer:
[tex]\frac{1}{9}[/tex] , 3 , 10
Step-by-step explanation:
Using the rules of exponents
[tex]a^{-m}[/tex] = [tex]\frac{1}{a^{m} }[/tex]
[tex]a^{\frac{m}{n} }[/tex] = [tex]\sqrt[n]{a^m}[/tex]
[tex]a^{0}[/tex] = 1
(a)
[tex]6^{-x}[/tex] = [tex]\frac{1}{6^{x} }[/tex] = [tex]\frac{1}{9}[/tex]
(b)
[tex]6^{\frac{x}{2} }[/tex] = [tex]\sqrt{6^{x} }[/tex] = [tex]\sqrt{9}[/tex] = 3
(c)
[tex]6^{0}[/tex] + [tex]6^{x}[/tex] = 1 + 9 = 10
