Question

A sample of xenon gas occupies a volume of 5.24 L at 411 K. If the pressure remains constant, at what temperature will this
same xenon gas sample have a volume of 2.06 L?

Answer 1

Answer:

161.57 K

Explanation:

V1/T1 = v2/T2

(5.24 L)/(411 K) = (2.06 L)/T2

T2 = 161.57 K