Question

Calculate the elastic potential energy when a 1000 N/m spring is stretched by 6.0 cm from
its natural length
Value
Units
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Hint 1
Hint 2
Essential GCSE Physics 37.4
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37. Springs and Elastic Deformation
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Calculate the elastic potential energy when a 1000 N/m spring is stretched by 6.0 cm from its natural length

Answer 1

Answer:

F = - k x     restoring force

PE = 1/2 k x^2      stored potential energy

PE = 1/2 * 1000 N/m * (.06 m)^2 = 1.8 N-m = 1.8 Joules