Question

Write an equation of the line that is perpendicular to the line whose equation is 2y=3x+12 and passes through the origin

Answer 1

the slope of the line 2y=3x+12, is 3/2, because when you divide both sides of the equation, you get y=(3/2)x+6
the perpendicular line has a slope -2/3
so the equation is y=(-2/3)x. (because the line passes thought the origin, the y intercept is 0)
Answer is in bold.