Answer:
see explanation
Step-by-step explanation:
(b)
Using the cosine ratio in the right triangle
cos65° = [tex]\frac{adjacent}{hypotenuse}[/tex] = [tex]\frac{BC}{AB}[/tex] = [tex]\frac{4.5}{x}[/tex] ( multiply both sides by x )
x × cos65° = 4.5 ( divide both sides by cos65° )
x = [tex]\frac{4.5}{cos65}[/tex] ≈ 10.6 ( to 1 dec. place )
(7)
Δ QRP and Δ QMK are similar the the ratios of corresponding sides are equal
[tex]\frac{QR}{QM}[/tex] = [tex]\frac{QP}{QK}[/tex] , substitute values
[tex]\frac{x}{60}[/tex] = [tex]\frac{80}{50}[/tex] ( cross- multiply )
50x = 4800 ( divide both sides by 50 )
x = 96
