Question

the equation of straight line is 3x+2y=6
a) write down the gradient of this line
b) write down the coordinates of the point where the line crosses the y-axis.

Answer 1

Answer:

gradient = - $\frac{3}{2}$ , y- intercept = (0, 3 )

Step-by-step explanation:

The equation of a line in slope- intercept form is

y = mx + c ( m is the gradient and c the y- intercept )

Given

3x + 2y = 6 ( subtract 3x from both sides )

2y = - 3x + 6 ( divide terms by 2 )

y = - $\frac{3}{2}$ x + 3 ← in slope- intercept form

with gradient m = - $\frac{3}{2}$ and y- intercept c = 3 ⇒ (0, 3 )