Question

pls help me in geometry, i really need it. thank u :)​

Answer 1

Answer:

a) $7\sqrt{2}$,  b and c)$\sqrt{65}$

Step-by-step explanation:

The length of line joining two coordinates (x₁,y₁) and (x₂,y₂) is

$\sqrt{(y_{2}-y_{1})^2+(x_{2}-x_{1})^2 }$

Using this formula for part a,

$AB=\sqrt{(3-(-4))^2+(3-(-4))^2} \\\\AB=\sqrt{2(49)} \\\\AB=7\sqrt{2}$

Using the formula for part b,

$AB=\sqrt{(-4-3)^2+(2-(-2))^2} \\\\AB=\sqrt{65}$

Using the formula for part c,

$AB=\sqrt{(1-0)^2+(4-(-4))^2} \\\\AB=\sqrt{65}$