Answer:
2x2+9x=x−368=0
- 2x^{2}+9x-\left(x-368\right)=0
2x2+9x−(x−368)=0
- 2x^{2}+{\color{#c92786}{9x}}{\color{#c92786}{-x}}+368=0
2x2+9x−x+368=0
2x2+8x+368=0
2(x2+4x+184)=0
=
−±2−4√2
x=\frac{-{\color{#e8710a}{b}} \pm \sqrt{{\color{#e8710a}{b}}^{2}-4{\color{#c92786}{a}}{\color{#129eaf}{c}}}}{2{\color{#c92786}{a}}}
x=2a−b±b2−4ac
Once in standard form, identify a, b and c from the original equation and plug them into the quadratic formula.
2+4+
18
4=0
x^{2}+4x+184=0
x2+4x+184=0
=1
a={\color{#c92786}{1}}
a=1
=4
b={\color{#e8710a}{4}}
b=4=
184
c={\color{#129eaf}{184}}
c=184
=−4±42−4⋅1⋅184√2⋅1
Multiply the numbers
Subtract the numbers
Multiply the numbers
=−4±−720√2
Step-by-step explanation:
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