Hello SuspiciousBaka!
[tex] \huge \boxed{\mathfrak{Question} \downarrow}[/tex]
Find the perimeter of the rectangle.
[tex] \large \boxed{\mathbb{ANSWER\: WITH\: EXPLANATION} \downarrow}[/tex]
Given,
- area of the rectangle = 102 cm²
- length of the rectangle = 17 cm.
First, we have to find the area of the rectangle. We know that, area of a rectangle = length × width. So..
[tex] \tt \: area = length \: \times \: width \\ \tt \: 102 = 17 \times width \\ \tt \: \frac{102}{17} = width \\ \underline{\underline{\tt \: 6 \: cm \: = \: width}}[/tex]
So, the width of the rectangle is 6 cm.
Now, let's find the perimeter of the rectangle. The formula for finding the perimeter is ⇨ perimeter = 2 (length + width). So..
[tex] \tt \: perimeter = 2(length + width) \\ \tt \: perimeter = 2(17 + 6) \\ \tt \: perimeter = 2 \times 23 \\ \boxed{\boxed{ \bf \: perimeter = 46 \: cm}}[/tex]
- The perimeter of the rectangle is 46 cm.
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Hope it'll help you!
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