Question

y = 6(x – 3)2 + 4
How do I rewrite the quadratic function in standard form

Answer 1

Answer:

6x^2 -36x + 58

Step-by-step explanation:

expand (x-3)^2 = x^2 -6x +9

6(x-3)^2 +4=6(x^2 -6x +9) +4 =6x^2 -36x + 54 +4 = 6x^2 -36x + 58