Question

Iodine-131 is a radioactive form of iodine. After the crisis at a Japanese nuclear power plant in March 2011, elevated levels of this substance were detected thousands of miles away from Japan. Iodine-131 has a half-life of 8 days. What is the daily decay factor for this substance

Answer 1

Iodine-131 is a radioactive form of iodine. After the crisis at a Japanese nuclear power plant in March 2011, elevated levels of this substance were detected thousands of miles away from Japan. The daily decay factor for this substance is 0.917

A radioactive element has unstable nuclei which give off atomic radiation during the process of gaining stability.

From the given information;

• suppose the amount of the radioactive iodine substance = l
• half-life in which the radioactive substance is reduced to in 8 days is = $\mathbf{\dfrac{l}{2}}$

If we assume that "d" should be the daily decay constant;

The daily decay constant can be calculated by using the formula:

$\mathbf{\dfrac{l}{2} = l \times d^8}$

$\mathbf{\dfrac{1}{2} = d^8}$

$\mathbf{d = (\dfrac{1}{2})^{1/8}}$

$\mathbf{ d =\sqrt[8]{\dfrac{1}{2}} }$

d = 0.917

Therefore, we can conclude that the daily decay factor for this substance is 0.917

Learn more about the daily decay factor here:

https://brainly.com/question/23657626?referrer=searchResults