Question

Suppose that 3 boys and 2 girls go to the theater and occupy 5 seats in a row. In how many ways can they be seated if all boys sit together?

A-3
B-6
C-12
D-36

Answer 1

The answer to the problem is as follows:

Count all boys as one unit. Then there is one boy and 2 girls who can be permuted in 3! = 6 ways. Bout the 3 boys can permute among themselves in 3! = 6 ways.
 
6x6 = 36 ways in which all boys are together.

I hope my answer has come to your help. God bless and have a nice day ahead!