Respuesta :
The solution to the problem is as follows:
Let be X: scores of SAT
P(X ≥ x) = 0.9
P((X - 500)/100 ≥ (x - 500)/100) = 0.9
P(Z ≥ z) = 0.9
z = 1.28
1.28 = (x - 500)/100
128 + 500 = x
x = 628
I hope my answer has come to your help. God bless and have a nice day ahead!
Let be X: scores of SAT
P(X ≥ x) = 0.9
P((X - 500)/100 ≥ (x - 500)/100) = 0.9
P(Z ≥ z) = 0.9
z = 1.28
1.28 = (x - 500)/100
128 + 500 = x
x = 628
I hope my answer has come to your help. God bless and have a nice day ahead!