Question

You are throwing darts at a dart board. You have a 1/ 6 chance of striking the bull's-eye each time you throw. If you throw 3 times, what is the probability that you will strike the bull's-eye all 3 times?

A. 5 /136

B. 1/ 216

C. 3/ 233

D. 1/ 100

Answer 1

B. 1/216

bc 1/6*1/6*1/6

Answer 2

Answer: B. $\frac{1}{216}$

Step-by-step explanation:

Given: The chances of striking the bull's-eye each time of throw =\frac{1}{6}

Since, if we throe dart on dart board , each event will be independent of the other.

Then, If we throw 3 times, what is the probability that we will strike the bull's-eye all 3 times is given by :-

$\text{P(strike bull's-eye)}=\frac{1}{6}\times\frac{1}{6}\times\frac{1}{6}=\frac{1}{216}$

Hence, the probability that we will strike the bull's-eye all 3 times is $\frac{1}{216}$.