Question

$\left \{ {{a^2 -2a-b^2=0} \atop {2b+2ab=0}} \right.$
Help me solve this plsss

Answer 1

Given :-

• a² - 2a - b² = 0
• 2b + 2ab = 0

To find :-

• Value of a and b .

Solution :-

Taking second equation:-

• 2b + 2ab = 0
• 2b ( 1 + a ) = 0
• 2b = 0 or (1+a) = 0
• b = 0 , a = -1

Substitute in first equation :-

• a² - 2a - b² = 0

When b = 0 ,

• a² - 2a - 0² = 0
• a² - a = 0
• a( a -1) =0
• a = 0 , 1

When a = -1 ,

• (-1)² - 2*(-1) - b² = 0
• 1 + 2 - b² = 0
• b² = 3
• b = ±√3

Answer :-

• a = 0,1 ; b = 0
• a = -1 , b = ±√3