Question

A plane starting at rest at one end of a runway undergoes a uniform acceleration of 4.8 m/s
2
for 15 s before take-off. What is its speed of takeoff?

Answer 1

• initial velocity=0m/s=u
• Acceleration=a=4.8m/s^2
• Time=t=15s

Final velocity be v

$\\ \sf\longmapsto v=u+at$

$\\ \sf\longmapsto v=0+4.8(15)$

$\\ \sf\longmapsto v=72m/s$