Question

A bike tire at a pressure of 740 mmHg and a
temperature of 290 K has a volume of 2.2 liters.
A child gets on the bike and rides it outside.
What is the new pressure if the temperature
outside is 296 K and his weight causes the tire's
volume to drop to 2.0 liters?

Answer 1

Answer: The new pressure is 831 mm Hg

Explanation:

The combined gas equation is,

$\frac{P_1V_1}{T_1}=\frac{P_2V_2}{T_2}$

where,

$P_1$ = initial pressure of gas = 740 mm Hg

$P_2$ = final pressure of gas = ?

$V_1$ = initial volume of gas = 2.2 L

$V_2$ = final volume of gas = 2.0 L

$T_1$ = initial temperature of gas = 290 K

$T_2$ = final temperature of gas = 296 K

Now put all the given values in the above equation, we get:

$\frac{740\times 2.2}{290}=\frac{P_2\times 2.0}{296}$

$P_2=831mmHg$

The new pressure is 831 mm Hg