the equation of each line using the given y- intercept and x- intercept
is [tex]y= -\frac{2}{3} x-2[/tex]
Given :
given the y- intercept and x- intercept . y intercept ( 0, -2) and x intercept is (-3, 0)
We need to frame the equation of the line y=mx+b
where m is the slope and b is the y intercept
y intercept is (0,-2) so the value of b=-2
Now we find slope using two points (0,-2) and (-3,0)
Apply slope formula
[tex]slope m =\frac{y_2-y_1}{x_2-x_1} =\frac{0+2}{-3+0} =-\frac{2}{3}[/tex]
We got the slope m and y intercept b =-2
Replace it in y=mx+b to get the equation of the line
[tex]y=mx+b\\y=-\frac{2}{3} x-2[/tex]
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