Question

find the equation of the line through the point (6,-1) that is perpendicular to 4x+3y=9

Answer 1

Answer:

Step-by-step explanation:

4x+3y=9

3y = -4x + 9

y = - 4/3x + 9/3

y = - 4/3x + 3

Slope -4/3 and slope of the perpendicular line: 3/4, point(6,-1)

b = -1 - (3/4)(6)

b = -1 -9/2 = -11/2

y = 3/4x - 11/2