Write the formula of a coordination compound made of two complex ions: one a complex of v(iii) with two ethylenediamine molecules and two cl− ions as ligands and the other a complex of ni(ii) having a coordination number of 4 with cl− ions as ligands.

Respuesta :

The answer is:  " [V₍en₎₂Cl]₂ [NiCl] " .
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Explanation:
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Note that:  
 [V³⁺ ₍en₎₂ (Cl⁻)²] is a "+1" charged cation;  and that:+1 ion 

[Ni²⁺ (Cl⁻)₄ is a "-2" charged anion; 

As such:  the chemical formula for the compound is written as:
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                             →   "[V₍en₎₂Cl]₂ [NiCl]  
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 The answer is:  " [V₍en₎₂Cl]₂ [NiCl] " .
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