Question

f(t)=t+2

g(t)=t^2-2

find f(1)-g(1)

^2 is meant to be an exponent

Answer 1

Answer:

$f(1) -g(1) = 4$

Step-by-step explanation:

Solving for $f(1)$:

$f(1) = 1 +2 \\ f(1) = 3$

Solving for $g(1)$:

$g(1) = 1^2 -2 \\ g(1) = 1 -2 \\ g(1) = -1$

Solving for $f(1) -g(1)$:

$f(1) -g(1) = 3 -(-1) \\ f(1) -g(1) = 3 +1 \\ f(1) -g(1) = 4$