Answer: Choice D. [tex]\frac{5}{2}[/tex]
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Work Shown:
[tex]\frac{7}{3}\cdot \frac{15}{14}\\\\\frac{7*15}{3*14}\\\\\frac{7*5*3}{3*7*2}\\\\\frac{7*5}{7*2} \ \text{ .... pair of 3s cancel}\\\\\frac{5}{2} \ \text{ .... pair of 7s cancel}\\\\[/tex]
As you can see, the goal is to factor the numbers so that we find stuff that cancels out. By the time we reach 5/2, there isn't anything left to cancel. Therefore, the fraction is fully reduced at this point.
