8. A bag of Skittles candy contains 8 red, 12 blue, 4 green, and 6 orange. What is
the probability of randomly choosing a green candy, replacing that candy and
choosing another green candy? *

Respuesta :

Answer:

it is a 26:4 probability if you simplify it it would be 6.5:1

Step-by-step explanation:

The probability of randomly choosing a green candy, replacing that candy and  choosing another green candy is 1/75 and this can be determined by using the given data.

Given :

A bag of Skittles candy contains 8 red, 12 blue, 4 green, and 6 orange.

The following steps can be used in order to determine the probability of randomly choosing a green candy, replacing that candy and  choosing another green candy:

Step 1 - First, determine the total number of candies in the bag.

[tex]\rm Total\; Candy = 8 + 12 + 4 +6[/tex]

[tex]\rm Total\; Candy = 30[/tex]

Step 2 - The total number of green candies in the bag is 4.

Step 3 - So, the probability of randomly choosing a green candy, replacing that candy and  choosing another green candy is:

[tex]P = \dfrac{4}{30}\times \dfrac{3}{30}[/tex]

Step 4 - Simplify the above expression.

[tex]P = \dfrac{12}{900}[/tex]

[tex]p=\dfrac{1}{75}[/tex]

The probability of randomly choosing a green candy, replacing that candy and  choosing another green candy is 1/75.

For more information, refer to the link given below:

https://brainly.com/question/795909

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