From the information given:
∴
The volume of the sterling silver pendant is:
= 61.3 mL - 50.0 mL
= 11.3 mL
Since, 1 mL = 1cm³
Then;
11.3 mL = 11.3 cm³
Using the relation for Density; i.e.
[tex]\mathbf{Density = \dfrac{mass}{volume}}[/tex]
[tex]\mathbf{10.25 \ g/cm^3= \dfrac{mass}{11.3 \ cm^3}}[/tex]
mass = 10.25 g/cm³× 11.3 cm³
mass of the sterling silver = 115.825 grams
Recall that sterling silver has:
∴
The mass of the copper contained in the sterling silver pendant can be calculated as:
[tex]\mathbf{= \dfrac{115.825 \ g \times 7.5}{100}}[/tex]
= 8.687 grams
Therefore, we can conclude that the mass of the copper contained in the sterling silver pendant is 8.687 grams
Learn more about the relation between Density, Mass, and Volume here:
https://brainly.com/question/24386693?referrer=searchResults