Question

a 4.0 kg ball is attached to 0.70 m string and spun at 2.0 m/s. what is the centripetal acceleration ?

Answer 1

a(cp) = v^2/R

a(cp) = (2.0)^2/0.70

a(cp) = 4.00/0.70

a(cp) = 5.7 m/s^2 (approximately)

Answer 2

Hope this helps, have a great day ahead!