Question

If mean of first 3 digits is 19 and next 2 digits is 18, what would be the mean of all 5 digits?

Answer 1

Mean of total 5 digits is 18.6

Given:

Mean of first 3 digit = 19

Mean of next 2 digit = 18

Find:

Mean of total 5 digits

Computation:

Sum of first 3 digit = Mean of first 3 digit × Number of digits

Sum of first 3 digit = 19 × 3

Sum of first 3 digit = 57

Sum of next 2 digit = Mean of first 3 digit × Number of digits

Sum of next 2 digit = 18 × 2

Sum of next 2 digit = 36

Total of 5 digit = Sum of first 3 digit + Sum of next 2 digit

Total of 5 digit = 57 + 36

Total of 5 digit = 93

Mean of total 5 digits = Total of 5 digit / 5

Mean of total 5 digits = 93 / 5

Mean of total 5 digits = 18.6

Learn more:

https://brainly.com/question/16645147?referrer=searchResults

Answer 2

The answer is "mean of all 5 digits is 18.6" and the further calculation can be defined as follows:

• The mean would be the total number divided by the number of numbers. To obtain the mean, we add all the numbers and divide by number.
• It is also known as the "average" value, which was established by summing all data points then divided by the information gain amount.
• Its most popular statistics used to measure the center of a collection of data and analysis are the statistics sometimes referred to it as average by statistics.
• In this question, let the value are a,b,c..., and e So,

Mean of 3 digits:

$\to \bold{\frac{a+b+c}{3}}=19$

Mean of 2 digits:

$\to \bold{\frac{d+e}{2}}=18$

Find:

Mean of all 5 digits =?

Calculating the sum of 3 digits:

$\to \bold{\frac{a+b+c}{3}}=19\\\\\to \bold{a+b+c}=19 \times 3\\\\\to \bold{a+b+c}=57$

Calculating the sum of 2 digits:

$\to \bold{\frac{d+e}{2}}=18\\\\\to \bold{d+e}=18\times 2\\\\\to \bold{d+e}=36$

Calculating the Mean of all 5 digits:

$\to \bold{\frac{a+b+c+d+e}{5}}= \bold{\frac{57+36}{5}}$

                       $= \bold{\frac{93}{5}}\\\\=\bold{18.6}$

So, the mean of all 5 digits is "18.6".

Learn more:

brainly.com/question/2003309