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[tex]x^2-6x+y^2-8x=0[/tex]

The graph of the given equation in the xy-plane is a circle. What is the radius of the circle? (You may NOT use a calculator!)

A) 2
B) 3
C) 4
D) 5

An explanation along with the answer would be extremely helpful!!! Thank you!

Respuesta :

s1m1

Answer:

D

Explanation:

Start with the general equation of a circle

(x-h)² + (y-k)² = r²

where (h, k) are the coordinates of the center, and r is the radius

x²-6x+y²-8y = 0 , form prefect squares while keeping the equation balanced

x²-6x + +y²-8y + = +

(x-3)² +(y-4)² = 9 + 16

(x-3)² +(y-4)² = 25

(x-3)² +(y-4)² = 5² , compare with (x-h)² + (y-k)² = r²

Radius = 5

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