Step-by-step explanation:
[tex](2-i)z=8z^2[/tex]
[tex]8z^2+(i-2)z=0[/tex]
[tex](8z+i-2)z=0[/tex]
Therefore, either
[tex]z=0[/tex]
or
[tex]8z+i-2=0[/tex]
[tex]z=\frac14-\frac18i[/tex]
