Question

There are 15 cards, numbered 1 through 15. If you pick a card, what is the probability that you choose an odd number or a two?



A)
2
3

B)
3
5


C)
8
15


D)
8
225

Answer 1

There are 8 odd number between 1 and 15 (1,3,5,7,9,11,13,15), so the probability of choosing an odd number is $\dfrac{8}{15}$.

The probability of choosing 2 is $\dfrac{1}{15}$.

So, the overall probability is equal to $\dfrac{8}{15}+\dfrac{1}{15}=\dfrac{9}{15}=\dfrac{3}{5}$

Answer 2

Answer:

Option B

Step-by-step explanation:

Given that the 15 cards are numbered 1 to 15.

A card is picked at random.  We have to find the probability that the card is odd or two

Let A - selected card is odd

B - selected card is 2

A and B are mutually exclusive

Hence P(AUB) = P(A)+P(B)

Since there are 1,3....15 i.e. 8 odd numbered cards

P(A) = 8/15

P(B) = 1/15 (since there is only one two)

Thus required prob = P(AUB) = 8/15+1/15

=9/15

=3/5

Hence option B