Question

Determine the type and number of solutions of 4x - 4x + 1 = 0.

two real solutions
one real solution
two imaginary solutions​

Answer 1

Answer:

1 real solution

Step-by-step explanation:

Use discramint formula.

$b {}^{2} - 4ac$

If the discramint >0, the equation is going to have 2 real solutions

If the discramint =0, we going to have one real solution.

If the discramint<0, we going to have two imaginary solution

B is -4, A is 4 and C is 1 so

${ - 4}^{2} - 4( 4)(1) = 0$

So the equation had one real solution.