Question

An alloy that is 30% silver is mixed with 200 g of a
10% silver alloy. How much of the 30% alloy must
be used to obtain an alloy that is 24% silver?
show work plz

Answer 1

Answer:

The answer is $466\frac{2}{3}\,g$

Step-by-step explanation:

Let,

Amount of alloy with 30% silver = x g

Given,

Amount of alloy with 10% silver = 200 g

So, Total Amount of alloy with 24% silver = (x+200) g

Now,

$x*0.30+200*0.10=(x+200)*0.24\\=>0.30x+20=0.24x+48\\=>0.06x=28\\x=466\frac{2}{3}\,g=466.67\,g$

Hope you have understood this....

pls mark my answer as the brainliest