Question

An object of mass 0.5 kg is swung in uniform circular motion. The radius is 2 meters, and the force exerted is 4 N. Calculate the magnitude of the velocity.

Answer 1

using
F= mv²/r
4 = 0.5×v² / 2
8 /0.5 = v²
v²=16
v= √16
v= 4 ms-¹

Answer 2

The magnitude of the velocity swung in uniform circular motion is equal 4 m/s.

Given the following data:

• Mass of object = 0.5 kg

• Radius = 2 meters

• Force = 4 Newton

To calculate the magnitude of the velocity:

Mathematically, centripetal force is given by the formula:

$F_c = \frac{mv^2}{r}$

Making v the subject of formula, we have:

$V = \sqrt{\frac{F_c r}{m} }$

Substituting the parameters into the formula, we have;

$V = \sqrt{\frac{4 \times 2}{0.5} }\\\\V = \sqrt{\frac{8}{0.5} }\\\\V =\sqrt{16}$

V = 4 m/s

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