The solution to a system of two linear equations is (4, -3). One equation has a slope of 4. The slope of the other line is the negative reciprocal of the slope of the first.


The system described above is represented by the following equations:

The solution to a system of two linear equations is 4 3 One equation has a slope of 4 The slope of the other line is the negative reciprocal of the slope of the class=

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caylus

Answer:

Hello,

First equation is false

Second equation is true

Step-by-step explanation:

1)

(4,-3) is a point of the line y=4x-19  since

-3=?4*4-19

-3=-3

2)

(4,-3) is not a point of the line y=1/4x-2 since

-3=? 1/4*4-2

-3=? 1-2

-3≠-1

I have written that because it is difficult for me to understand

"the negative reciprocal of the slope of the first"

the negative reciprocal of 4 should be -1/4.

Equation y=1/4x-2 is false.

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