Respuesta :
Answer:
He should have multiplied by [tex]\frac{3}{3}[/tex] and not [tex]\frac{1}{3}[/tex]
The fraction is greater than
Step-by-step explanation:
Given
[tex]\frac{2}{3}\ \&\ \frac{5}{9}[/tex]
Sadi's steps are:
The common denominator is 9.
[tex]\frac{2}{3} * \frac{1}{3} = \frac{2}{9}[/tex]
[tex]\frac{2}{9} < \frac{5}{9}[/tex]
So:
[tex]\frac{2}{3} < \frac{5}{9}[/tex]
Required
Sadi's error
Her first error is that: he should have multiplied by [tex]\frac{3}{3}[/tex] and not [tex]\frac{1}{3}[/tex]
This is so because, whatever factor is multiplied to the numerator has to be multiplied to the denominator, as well.
So, we have:
[tex]\frac{2}{3} * \frac{3}{3} = \frac{6}{9}[/tex]
By comparison:
[tex]\frac{6}{9} > \frac{5}{9}[/tex]
So, his second error is that: the fraction is greater than
Answer:
B. He should have multiplied 2/3 by 3/3 not 1/3
D. The fraction 2/3 is greater than 5/9, not less
than 5/9.
Step-by-step explanation:
Just did it on EDGE2021 and got it right :D
